If the resistance in a DC circuit is constant and the voltage doubles, what happens to the current?

When analyzing a DC circuit where the resistance remains constant and the voltage doubles, we can apply Ohm's Law, which expresses the relationship between voltage (V), current (I), and resistance (R) in the formula: V = I × R.

In this scenario, if the voltage is increased (doubled) while the resistance does not change, we can rearrange Ohm's Law to find the new current. By isolating current in the equation, we have I = V/R. If the original voltage is represented as V_1, and the new voltage as V_2 (where V_2 = 2 * V_1), we can express the relation of the currents as I_1 = V_1/R and I_2 = V_2/R.

Substituting in the new voltage gives us I_2 = (2 * V_1) / R. Comparing the two currents shows that I_2 = 2 * (V_1/R), which tells us that the new current (I_2) is indeed twice the original current (I_1). Therefore, the current doubles when the voltage is doubled, given that resistance remains constant.

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